Python编写游戏怎么运行(Python基础——用 Python 写个消消乐小游戏)

提到开心消消乐这款小游戏，相信大家都不陌生，其曾在 2015 年获得过玩家最喜爱的移动单机游戏奖，受欢迎程度可见一斑，本文我们使用 Python 来做个简单的消消乐小游戏实现消消乐的构成主要包括三部分：游戏主体、计分器、计时器，下面来看一下具体实现。

先来看一下游戏所需 Python 库import osimport sysimport timeimport pygameimport random定义一些常量，比如：窗口宽高、网格行列数等，代码如下：。

WIDTH = 400HEIGHT = 400NUMGRID = 8GRIDSIZE = 36XMARGIN = (WIDTH - GRIDSIZE * NUMGRID) // 2YMARGIN = (HEIGHT - GRIDSIZE * NUMGRID) //

2ROOTDIR = os.getcwd()FPS = 30接着创建一个主窗口，代码如下：pygame.init()screen = pygame.display.set_mode((WIDTH, HEIGHT))pygame.display.set_caption(

消消乐)看一下效果：

再接着在窗口中画一个 8 x 8 的网格，代码如下：screen.fill((255,255,220))#游戏界面的网格绘制defdrawGrids(self):forxinrange(NUMGRID):

foryinrange(NUMGRID):rect=pygame.Rect((XMARGIN+x*GRIDSIZE,YMARGIN+y*GRIDSIZE,GRIDSIZE,GRIDSIZE))self.drawBlock(rect,

color=(255,165,0),size=1#画矩形block框defdrawBlock(self,block,color=(255,0,0),size=2):pygame.draw.rect(self.screen,

color,block,size)看一下效果：

再接着在网格中随机放入各种拼图块，代码如下：whileTrue: self.all_gems = [] self.gems_group = pygame.sprite.Group() for x in range(NUMGRID):

self.all_gems.append([]) for y in range(NUMGRID): gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE-NUMGRID*GRIDSIZE], downlen=NUMGRID*GRIDSIZE)

self.all_gems[x].append(gem) self.gems_group.add(gem) ifself.isMatch()[0] == 0: break看一下效果：

再接着加入计分器和计时器，代码如下：# 显示得分def drawScore(self): score_render = self.font.render(分数:+str(self.score), 1, (

85, 65, 0)) rect = score_render.get_rect() rect.left, rect.top = (55, 15) self.screen.blit(score_render, rect)# 显示加分def drawAddScore(

self, add_score): score_render = self.font.render(++str(add_score), 1, (255, 100, 100)) rect = score_render.get_rect() rect.left, rect.top = (

250, 250) self.screen.blit(score_render, rect)# 显示剩余时间def showRemainingTime(self): remaining_time_render =

self.font.render(倒计时: %ss % str(self.remaining_time), 1, (85, 65, 0)) rect = remaining_time_render.get_rect() rect.left, rect.top = (WIDTH-

190, 15) self.screen.blit(remaining_time_render, rect)看一下效果：

当设置的游戏时间用尽时，我们可以生成一些提示信息，代码如下：while True:foreventinpygame.event.get():ifevent.type==pygame.QUIT:pygame.quit()

sys.exit()ifevent.type==pygame.KEYUPandevent.key==pygame.K_r:flag=Trueif flag:breakscreen.fill((255,255

,220))text0=最终得分: %s%scoretext1=按 R 键重新开始y=140foridx,textinenumerate([text0,text1]):text_render=font.render(text,

1,(85,65,0))rect=text_render.get_rect()ifidx==0:rect.left,rect.top=(100,y)elifidx==1:rect.left,rect.top

=(100,y)y+=60screen.blit(text_render,rect)pygame.display.update()看一下效果：

说完了游戏图形化界面相关的部分，我们再看一下游戏的主要处理逻辑我们通过鼠标来操纵拼图块，因此程序需要检查有无拼图块被选中，代码实现如下：defcheckSelected(self, position):

for x in range(NUMGRID): for y in range(NUMGRID): ifself.getGemByPos(x, y).rect.collidepoint(*position):

return [x, y] return None我们需要将鼠标连续选择的拼图块进行位置交换，代码实现如下：def swapGem(self, gem1_pos, gem2_pos): margin = gem1

_pos[0] - gem2_pos[0] + gem1_pos[1] - gem2_pos[1] if abs(margin) != 1: return False gem1 = self.getGemByPos(

*gem1_pos) gem2 = self.getGemByPos(*gem2_pos) if gem1_pos[0] - gem2_pos[0] == 1: gem1.direction = left gem2.direction = right elif gem1_

pos[0] - gem2_pos[0] == -1: gem2.direction = left gem1.direction = right elif gem1_pos[1] - gem2_pos[1] == 1: gem1.direction = up gem2.direction = down elif gem1_

pos[1] - gem2_pos[1] == -1: gem2.direction = up gem1.direction = down gem1.target_x = gem2.rect.left gem1.target

_y = gem2.rect.top gem1.fixed = False gem2.target_x = gem1.rect.left gem2.target_y = gem1.rect.top gem2.fixed = False self.all_

gems[gem2_pos[0]][gem2_pos[1]] = gem1 self.all_gems[gem1_pos[0]][gem1_pos[1]] = gem2 return True每一次交换拼图块时，我们需要判断是否有连续一样的三个及以上拼图块，代码实现如下：

defisMatch(self): for x in range(NUMGRID): for y in range(NUMGRID): if x + 2 < NUMGRID:ifself.getGemByPos(x, y).type ==

self.getGemByPos(x+1, y).type == self.getGemByPos(x+2, y).type:return [1, x, y] if y + 2 < NUMGRID:

ifself.getGemByPos(x, y).type == self.getGemByPos(x, y+1).type == self.getGemByPos(x, y+2).type:return

[2, x, y] return [0, x, y]当出现三个及以上拼图块时，需要将这些拼图块消除，代码实现如下：defremoveMatched(self, res_match): if res_match[

0] > 0: self.generateNewGems(res_match) self.score += self.reward returnself.reward return0将匹配的拼图块消除之后，我们还需要随机生成新的拼图块，代码实现如下：

def generateNewGems(self, res_match): if res_match[0] == 1: start = res_match[2] while start > -2: for each in [res_

match[1], res_match[1]+1, res_match[1]+2]: gem = self.getGemByPos(*[each, start]) if start == res_match[2]: self.gems_group.remove(gem) self.all_gems[each][start] = None elif start >= 0: gem.target_y += GRIDSIZE gem.fixed = False gem.direction = down self.all_gems[each][start+1] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+each*

GRIDSIZE, YMARGIN-GRIDSIZE], downlen=GRIDSIZE) self.gems_group.add(gem) self.all_gems[each][start+1

] = gem start -= 1 elif res_match[0] == 2: start = res_match[2] while start > -4: if start == res

_match[2]: for each in range(0, 3): gem = self.getGemByPos(*[res_match[1], start+each]) self.gems

_group.remove(gem) self.all_gems[res_match[1]][start+each] = None elif start >= 0: gem = self.getGemByPos(

*[res_match[1], start]) gem.target_y += GRIDSIZE * 3 gem.fixed = False gem.direction = down self.all

_gems[res_match[1]][start+3] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[

XMARGIN+res_match[1]*GRIDSIZE, YMARGIN+start*GRIDSIZE], downlen=GRIDSIZE*3) self.gems_group.add(gem) self.all_

gems[res_match[1]][start+3] = gem start -= 1之后反复执行这个过程，直至耗尽游戏时间，游戏结束。最后，我们动态看一下游戏效果。

总结本文我们使用 Python 实现了一个简单的消消乐游戏，有兴趣的可以对游戏做进一步扩展，比如增加关卡等另外：开头的import os 和 import pygame报错，应该怎么办？需要你 pip install 一下。

亲爱的读者们，感谢您花时间阅读本文。如果您对本文有任何疑问或建议，请随时联系我。我非常乐意与您交流。